C program for Anagram checking

      The below program is to check whether two words are anagrams or not.The concept used is that we store the frequency of an alphabet in a word .By checking those counts we determine whether they are anagrams  or not ....count same == anagrams.

#include <stdio.h>
#include<conio.h>
int anagramchecker(char [],char []); //declaration of funtion
int main()
{
   char word1[50], word2[50];
   printf("Enter first word:\n");
   gets(word1);
   printf("Enter second word:\n");
   gets(word2);
   anagramchecker(word1,word2); //calling function to check anagrams
   getch(); return 0;
}

int anagramchecker(char a[], char b[])
{
  int counta[26] = {0}, countb[26] = {0},i= 0;
  while (a[i] != '\0')

   {
     counta[a[i]-'a']=counta[a[i]-'a']+1;
  i++;
  }
  i= 0;
  while (b[i] != '\0')
  {
    countb[b[i]-'a']= countb[b[i]-'a']+1;
   i++;
 }
for (i = 0; i< 26; i++)
{
  if (counta[i] != countb[i])
    {
       printf("Given words are not anagrams.\n");
       return 0;
    }
 }
 printf("Given words are anagrams.\n");
 return 1;
}